Java duplicate a file

See copy - one can leave out the vararg copy options, or do Files. Files class? Yes, my automatic pilot leaves me also at odds regularly. Show 1 more comment. Pierre Pierre 1 1 silver badge 9 9 bronze badges. Well you can write byte by byte so I suppose that should work — Pierre. Add a comment. Sign up or log in Sign up using Google. Sign up using Facebook.

Sign up using Email and Password. Post as a guest Name. Email Required, but never shown. It contains the FileUtils. The directory holding the destination file is created if it does not exist. If the destination file exists, then this method will overwrite it. Google Guava is an open-source set of common libraries for Java. It includes Files.

In this tutorial, we have shown several ways how to copy a file in Java. We have used built-in tools and third-party libraries. In this example, a class was declared as public with the name Person , but was saved in a file called Person2.

The error message is pretty explicit: "class Person is public, should be declared in a file named Person. The "duplicate class" error can sometimes be a little more tricky to resolve. One situation in which this occurs is when two source code directories include the same class with the same package structure. This error looks like that shown in the next screen snapshot.

As the above screen snapshot indicates, the class dustin. Person exists in both the src2 directory and not shown here in the src directory "duplicate class: dustin. Indeed, these are duplicate classes, at least in terms of package and class name. The "duplicate class" error can also occur when the class is named the same with the same package naming hierarchy, even if one of the classes exists in a directory structure with directory names different than the package names.

Your compare routine only tests the first byte of any files, so all your results are likely to be incorrect. You also do not need to convert this to a jar file, just run the class as created by the compiler. Gigabyte Giant 5-Sep pm. Do you know why at lines 17 and 46 I am getting a InputMismatchException?

Accept Solution Reject Solution. Your problem is due to the Scanner class trying to interpret the tokens from the input file and convert them to bytes. You need a basic stream reader that will allow you to read individual bytes from the file. Try this: Java. Posted 5-Sep am Richard MacCutchan. Thank you, that worked. Now from that I should be able to change this to the way I need it.

I really appreciate it, thank you good sir. Richard MacCutchan 6-Sep am. Happy to help, good luck with your further efforts. Add your solution here. OK Paste as.